The freezing point (in °C) of a solution containing 0.1 g of K 3 [Fe(CN) 6 ] (Mol. wt. =…
Chemistry · JEE Advanced · NTA Exams — Solutions
The freezing point (in °C) of a solution containing
0.1 g of K3[Fe(CN)6] (Mol. wt. = 329) in 100 g of water
(Kf = 1.86 K kg mol–1) is
0.1 g of K3[Fe(CN)6] (Mol. wt. = 329) in 100 g of water
(Kf = 1.86 K kg mol–1) is
- – 2.3 × 10–2
- – 5.7 × 10–2
- – 5.7 × 10–3
- – 1.2 × 10–2
Answer
(B) – 5.7 × 10 –2
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