Mixture of volatile components A and B has total vapour pressure (in torr) : P = 254 –…
Chemistry · JEE Advanced · NTA Exams — Solutions
Mixture of volatile components A and B has total vapour pressure (in torr) :
P = 254 – 119XA
where, XA is mole fraction of A in mixture. Hence \(\mathrm{p}_{\mathrm{A}}^{0} \text { and } \mathrm{p}_{\mathrm{B}}^{0}\) are (in torr) :
P = 254 – 119XA
where, XA is mole fraction of A in mixture. Hence \(\mathrm{p}_{\mathrm{A}}^{0} \text { and } \mathrm{p}_{\mathrm{B}}^{0}\) are (in torr) :
- 254, 119
- 119, 254
- 135, 254
- 154, 119
Answer
(C) 135, 254
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