Let A(1, 1, 1), B(2, 3, 5), C(–1, 0, 2) be three points, then equation of a plane…

Mathematics · JEE Advanced · NTA ExamsThree Dimensional Geometry

Let A(1, 1, 1), B(2, 3, 5), C(–1, 0, 2) be three points, then equation of a plane parallel to the plane ABC which is at distance 2 from plane ABC
  1. \(2 x-3 y+z+2 \sqrt{14}=0\)
  2. \(2 x-3 y+z-\sqrt{14}=0\)
  3. 2x – 3y + z + 2 = 0
  4. 2x – 3y + z – 2 = 0

Answer

(A) 2 x-3 y+z+2 14 =0

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