Two beams of light having intensities I and 4 I interfere to produce a fringe pattern on…
Physics · NEET · NTA Exams — Optics
Two beams of light having intensities \(\text { I }\) and 4\(\text { I }\) interfere to produce a fringe pattern on a screen. The phase difference between the beams is \(\frac{\pi}{2}\) at point A and π at point B. Then, the difference between the resultant intensities at A and B is
- 2\(\text { I }\)
- 4\(\text { I }\)
- 5\(\text { I }\)
- 7\(\text { I }\)
Answer
(A) 2 I
Sign up free on Edukali to view the step-by-step worked solution and practice thousands of similar questions.
Related practice questions
- Two thin lenses are of same focal length (A), but one is convex and the other one is concave. When they are…
- If the intensity ratio for two interfering coherent sources is II , then I_ max -I_ min I_ max +I_ min will…
- A thin glass (refractive index 1.5) lens has optical power of -5[] in air. Its optical power in liquid medium…
- An eye specialist prescribes having combination of convex lens of focal length 40 cm in contact with a…
- Two transparent media A and B are separated by a plane boundary. The speed of light in those media are 1.5…
- A ball is dropped from a height of 20 m above the surface of water in a lake. The refractive index of water…
- A narrow slit of width 1 mm is illuminated by monochromatic light of wavelength 600 nm. The distance between…
- A candle placed 25 cm from a lens, forms an image on a screen placed 75 cm on the other end of the lens. The…