If the intensity ratio for two interfering coherent sources is II , then I_ max -I_ min…
Physics · NEET · NTA Exams — Optics
If the intensity ratio for two interfering coherent sources is \(\text { II }\), then \(\frac{I_{\text {max }}-I_{\text {min }}}{I_{\text {max }}+I_{\text {min }}}\) will be equal to
- \(\frac{2 \pi}{1+\pi^{2}}\)
- \(\frac{4 \pi}{1+\sqrt{\pi}}\)
- \(\frac{2 \sqrt{x}}{x+1}\)
- \(\frac{2 \sqrt{x}}{1+x^{2}}\)
Answer
(C) 2 x x+1
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