At what angle must the two forces (x+y) and (x-y) act so that the resultant may be (x^ 2…
Physics · JEE Main · NTA Exams — Kinematics
At what angle must the two forces \((x+y) \text { and }(x-y)\) act so that the resultant may be \(\sqrt{\left(x^{2}+y^{2}\right)}\) ?
- \(\cos ^{-1}\left[-\frac{x^{2}+y^{2}}{2\left(x^{2}-y^{2}\right)}\right]\)
- \(\cos ^{-1}\left[\frac{-2\left(x^{2}-y^{2}\right)}{x^{2}+y^{2}}\right]\)
- \(\cos ^{-1}\left[-\frac{\left(x^{2}+y^{2}\right)}{\left(x^{2}-y^{2}\right)}\right]\)
- \(\cos ^{-1}\left[-\frac{\left(x^{2}-y^{2}\right)}{\left(x^{2}+y^{2}\right)}\right]\)
Answer
(D) ^ -1 [- (x^ 2 -y^ 2 ) (x^ 2 +y^ 2 ) ]
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