An equilibrium mixture of the reaction 2H 2 S(g) ⇌ 2H 2 (g) + S 2 (g) had 0.5 mole H 2 S…
Chemistry · JEE Main · NTA Exams — Equilibrium
An equilibrium mixture of the reaction
2H2S(g) \(\text { ⇌ }\) 2H2 (g) + S2(g)
had 0.5 mole H2S, 0.10 mole H2 and 0.4 mole S2 in one litre vessel. The value of equilibrium constant (K) in mole litre-1 is
2H2S(g) \(\text { ⇌ }\) 2H2 (g) + S2(g)
had 0.5 mole H2S, 0.10 mole H2 and 0.4 mole S2 in one litre vessel. The value of equilibrium constant (K) in mole litre-1 is
- 0.004
- 0.008
- 0.016
- 0.160
Answer
(C) 0.016
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