A buffer solution of pH = 9.00 is made by dissolving ammonium chloride and ammonia in…
Chemistry · JEE Advanced · NTA Exams — Equilibrium
A buffer solution of pH = 9.00 is made by dissolving ammonium chloride and ammonia in water. How many moles of ammonium chloride must be added to 1.0 L of 0.25 M ammonia to prepare this buffer ?
\(\mathrm{NH}_{3}(\mathrm{aq})+\mathrm{H}_{2} \mathrm{O} \rightleftharpoons \mathrm{NH}_{4}^{-}(\mathrm{aq})+\mathrm{OH}^{-}(\mathrm{aq}) ;\) Kb=1.8 × 10–5
\(\mathrm{NH}_{3}(\mathrm{aq})+\mathrm{H}_{2} \mathrm{O} \rightleftharpoons \mathrm{NH}_{4}^{-}(\mathrm{aq})+\mathrm{OH}^{-}(\mathrm{aq}) ;\) Kb=1.8 × 10–5
- 0.25 mol
- 0.45 mol
- 0.65 mol
- 2.2 mol
Answer
(B) 0.45 mol
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