Let cos (α + β) = 4 5 and let sin (α – β) = 5 13 , where 0 ≤ α, 4 . Then tan 2α is equal…
Mathematics · JEE Advanced · NTA Exams — Trigonometry
Let cos (α + β) = \(\frac{4}{5}\)and let sin (α – β) = \(\frac{5}{13},\)where 0 ≤ α, \(\beta \leq \frac{\pi}{4}\). Then tan 2α is equal to
- \(\frac{25}{16}\)
- \(\frac{56}{33}\)
- \(\frac{19}{12}\)
- \(\frac{20}{7}\)
Answer
(B) 56 33
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