The distance of the point (1, –5, 9) from the plane x – y + z = 5 measured along a…
Mathematics · JEE Main · NTA Exams — Three Dimensional Geometry
The distance of the point (1, –5, 9) from the plane
x – y + z = 5 measured along a straight line x = y = z is
x – y + z = 5 measured along a straight line x = y = z is
- \(3 \sqrt{5}\)
- \(10 \sqrt{3}\)
- \(5 \sqrt{3}\)

Answer
(B) 10 3
Sign up free on Edukali to view the step-by-step worked solution and practice thousands of similar questions.
Related practice questions
- If ( a b ) c = a ( b c ) , where a , b , c are any three vectors such that ≠ 0, b c ≠ 0, then a and c are
- If a point R(4, y, z) lies on the line segment joining the points P(2, -3, 4) and Q(8, 0, 10), then the…
- If the lines, x-1 2 = y+1 3 = z-2 4 meets the plane, x+2 y+3 z=15 at a point P, then the distance of P from…
- If line r =( i -2 j - k )+ (2 i + j +2 k ) is parallel to the plane r (3 i -2 j - m k )=4 then the value of m…
- Given below are two statements. STATEMENT - 1: The direction cosines of one of the angular bisectors of two…
- If a b = c d and a c = b d and a d , ~b c , Then
- If ABCDE is a pentagon, then AB + AE + BC + DC + ED + AC equals
- The angle between the straight lines whose direction cosines are given by 2|+2 m-n=0, m n+n|+ m=0, is
More Three Dimensional Geometry questions · Browse all practice questions