A spring of stiffness k is kept compressed by applying horizontal force on m by a length…
Physics · JEE Advanced · NTA Exams — Work, Energy and Power
A spring of stiffness k is kept compressed by applying horizontal force on m by a length x0 \(\left(=\frac{m g}{k}\right)\). If the force F is withdrawn suddenly, the block oscillates and finally stops. In consequence, frictional loss is equal to 50% of the initial potential energy stored in the spring. The coefficient of friction the between block and the ground is
- \(\frac{1}{2}\)
- \(\frac{2}{3}\)
- \(\frac{1}{\sqrt{2}}\)
- \(\frac{1}{\sqrt{3}}\)
Answer
(C) 1 2
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