The value of (1- + ^ 2 )^ 5 + (1+ - ^ 2 )^ 5 , where and ^ 2 are the complex cube roots…
Mathematics · JEE Main · NTA Exams — Complex Numbers and Quadratic Equations
The value of \(\left(1-\omega+\omega^{2}\right)^{5}+\left(1+\omega-\omega^{2}\right)^{5}\), where \(\omega\) and \(\omega^{2}\) are the complex cube roots of unity, is
- \(0\)
- \(32 \mathrm{~m}\)
- \(-32\)
- \(32\)
Answer
(C) -32
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