A particle moving along x-axis has acceleration f, at time t, given by f=f_ 0 (1- t T ) …
Physics · JEE Main · NTA Exams — Kinematics
A particle moving along x-axis has acceleration f, at time t, given by \(f=f_{0}\left(1-\frac{t}{T}\right)\), where f0 and T are constants. The particle at t = 0 has zero velocity. At the instant when f = 0, the particle’s velocity (v) is
- \(f_{0} T\)
- \(\frac{1}{2} f_{0} T^{2}\)
- \(f_{0} T^{2}\)
- \(\frac{1}{2} f_{0} T\)
Answer
(D) 1 2 f_ 0 T
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