Equivalent weight = n-factor is very important in redox as well as non-redox reactions…
Chemistry · JEE Advanced · NTA Exams — Some Basic Concepts in Chemistry
Equivalent weight =
n-factor is very important in redox as well as non-redox reactions. With the help of n-factor we can predicts the molar ratio of the reactant species taking part in reactions. The reciprocal of n-factor’s ratio of the reactants is the molar ratio of the reactants.
In general n-factor of acid/base is number of moles of
H+/OH– furnished per mole of acid/base. n-factor of a reactant is no. of moles of electrons lost or gained per mole of reactant.
Example 1 :
1 . In acidic medium : \(\mathrm{KMnO}_{4}(\mathrm{n}=5) \rightarrow \mathrm{Mn}^{2+}\)
2 . In neutral medium : \(\mathrm{KMnO}_{4}(\mathrm{n}=3) \rightarrow \mathrm{Mn}^{2+}\)
3 . In basic medium : \(\mathrm{KMnO}_{4}(\mathrm{n}=1) \rightarrow \mathrm{Mn}^{6+}\)
Example 2 :
\(\mathrm{FeC}_{2} \mathrm{O}_{4} \rightarrow \mathrm{Fe}^{3+}+2 \mathrm{CO}_{2}\)
Total no. of moles of e– lost by 1 mole of FeC2O4
= 1 + 1 × 2 \(\text { ⇒ }\) 3
\(\text { ∴ }\) n-factor of FeC2O4 = 3
n-factor of Ba(MnO4)2 in acidic medium is
- 2
- 6
- 10
- None of these
Answer
(C) 10
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