Often more than one reaction is required to change starting materials into the desired…
Chemistry · JEE Advanced · NTA Exams — Some Basic Concepts in Chemistry
Often more than one reaction is required to change starting materials into the desired product. This is true for many reaction that we carry out in the laboratory and for many industrial process. These are called sequential reactions. The amount of desired product from each reaction is taken as the starting material for the next reaction.
I : 2KClO3
2KCl + 3O2 II : 4Al + 3O2
2Al2 O3 KClO3 decomposes in step I to give O2, which in turn, is used by Al to form Al2O3 in step II. First we determine O2 formed in step I and then Al used by this O2 in step II. Both reactions can be added to determine amount of KClO3 that can give required amount of O2 needed for Al.
Net : 2KClO3 + 4Al
2KCl + 2Al2O3 Thus, 2KClO3 ≡ 4Al
Or KClO3 ≡ 2Al.
I : CaO + 3C
CaC2 + CO II : CaC2 + 2H2O
Ca(OH)2 + C2H2 CaC2 (calcium carbide) is prepared in step I. It is used to prepare acetylene (C2H2) in step II. Suppose we want to determine amount of CaO that can give enough CaC2 to converted required amount of C2H2. Amount of CaO is determined in step I and then amount of C2H2 in step II. We can relate CaO and C2H2 stoichiometrically by writing net reaction which is
CaO + 3C + 2H2 O
Ca(OH)2 + C2H2 + CO Thus, CaO ≡ C2H2
NX is produced by the following step of reactions
M + X2
M X2 MX2 + X2
M3X8 M3X8 + N2CO3
N X + CO2 + M3O4 How much M (metal) is consumed to produce 206 gm of NX. (Take At. wt of M = 56, N=23, X = 80)
- 42 gm
- 56 gm
- \(\frac{14}{3} \mathrm{gm}\)
- \(\frac{7}{4} \mathrm{gm}\)
Answer
(A) 42 gm
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