If P ( ~B )= 3 5 , P ( ~A / B )= 1 2 and P ( ~A ~B )= 4 5 then P ((A ∪ B)’) + P (A’ ∪ B) =
Mathematics · JEE Main · NTA Exams — Statistics and Probability
If \(\mathrm{P}(\mathrm{~B})=\frac{3}{5}, \mathrm{P}(\mathrm{~A} / \mathrm{B})=\frac{1}{2}\) and \(\mathrm{P}(\mathrm{~A} \cup \mathrm{~B})=\frac{4}{5}\)then
P ((A ∪ B)’) + P (A’ ∪ B) =
P ((A ∪ B)’) + P (A’ ∪ B) =
- \(\frac{1}{5}\)
- \(\frac{4}{5}\)
- \(\frac{1}{2}\)
- 1
Answer
(D) 1
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