In a Δ ABC, if the sides are a =3, ~b =5 and c =4 , then 2 + 2 is equal to
Mathematics · JEE Main · NTA Exams — Trigonometry
In a Δ ABC, if the sides are \(\mathrm{a}=3, \mathrm{~b}=5 \text { and } \mathrm{c}=4\), then \(\sin \frac{\theta}{2}+\cos \frac{\theta}{2}\) is equal to
- \(\sqrt{2}\)
- \(\frac{\sqrt{3}+1}{2}\)
- \(\frac{\sqrt{3}-1}{2}\)
- 1
Answer
(A) 2
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