If the binding energy per nucleon in Li 7 and He 4 nuclei are respectively 5.60 MeV and…
Physics · JEE Advanced · NTA Exams — Atoms and Nuclei
If the binding energy per nucleon in Li7 and He4 nuclei are respectively 5.60 MeV and 7.06 MeV, then energy of reaction Li7 + p → 2 2He4 is
- 19.6 MeV
- 2.4 MeV
- 8.4 MeV
- 17.3 MeV
Answer
(D) 17.3 MeV
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