Radioactive element decays to form a stable nuclide, then the rate of decay of reactant (…
Physics · JEE Advanced · NTA Exams — Atoms and Nuclei
Radioactive element decays to form a stable nuclide, then the rate of decay of reactant \(\left(\frac{\mathbb{N}}{\mathbb{d}}\right)\) will vary with time (t) as shown in figure
Answer
(C)
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