For a > 0, solve the equation for x: 2 _ x a+ _ a x a+3 _ a^ 2 x a=0
Mathematics · JEE Main · NTA Exams — Sets, Relations and Functions
For a > 0, solve the equation for x:
\(2 \log _{x} a+\log _{a x} a+3 \log _{a^{2} x} a=0\)
- a- 4/3, a1/2
- a- 4/3, a-1/2
- a4/3, a-1/2
- none of these
Answer
(B) a - 4/3 , a -1/2
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