Range of f (x) = sin –1 x + cot –1 x + tan –1 x is
Mathematics · JEE Main · NTA Exams — Sets, Relations and Functions
Range of f (x) = sin–1x + cot–1x + tan–1x is
- [0, π]
- \(\left[\frac{\pi}{2}, \pi\right]\)
- \(\left[\frac{\pi}{4}, \pi\right]\)
- [–π, π]
Answer
(A) [0, π ]
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