Range of f (x) = sin –1 x + cot –1 x + tan –1 x is

Mathematics · JEE Main · NTA ExamsSets, Relations and Functions

Range of f (x) = sin–1x + cot–1x + tan–1x is
  1. [0, π]
  2. \(\left[\frac{\pi}{2}, \pi\right]\)
  3. \(\left[\frac{\pi}{4}, \pi\right]\)
  4. [–π, π]

Answer

(A) [0, π ]

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