XY 2 dissociates as : X Y_ 2 X Y+Y Initial pressure of XY 2 is 600 mm Hg. The total…
Chemistry · JEE Main · NTA Exams — Equilibrium
XY2 dissociates as :
\(X Y_{2} \rightleftharpoons X Y+Y\)
Initial pressure of XY2 is 600 mm Hg. The total pressure at equilibrium is 800 mm Hg. Assuming volume of system to remain constant, the value of Kp is
\(X Y_{2} \rightleftharpoons X Y+Y\)
Initial pressure of XY2 is 600 mm Hg. The total pressure at equilibrium is 800 mm Hg. Assuming volume of system to remain constant, the value of Kp is
- 50
- 100
- 200
- 400
Answer
(B) 100
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