Find the least value of 'a' for which the function f(x)=x^ 2 +a x+1 is increasing on…
Mathematics · JEE Main · NTA Exams — Limit, Continuity and Differentiability
Find the least value of 'a' for which the function \(f(x)=x^{2}+a x+1\) is increasing on \([1,2]\).
- 2
- 1
- -1
- -2
Answer
(D) -2
Sign up free on Edukali to view the step-by-step worked solution and practice thousands of similar questions.
Related practice questions
- Let f(x)= array ll -1, & -2 x<0 x^ 2 -1, & 0 x 2 array . and g(x) = |f(x)| + f(|x|). Then, in the interval…
- The function f (x) = 2x 2 – log | x | monotonically decreases for
- If f(x)= x^ 2 2-2 x ; g(x)= x^ 2 6 x-6 x where 0 < x < 1, then :
- The value of _ x 3 ( _ a x-3 x+6 -3 ) is
- The maximum slope of the curve y = –x 3 + 3x 2 + 9x – 27 is
- If the tangent at each point of the curve y = 2 3 x 3 – 2ax 2 + 2x + 5 makes an acute angle with the positive…
- Consider the following statements S and R : S : Both sin x and cos x are decreasing functions in the interval…
- Let y(x) be a function of x satisfying the relation (x+y)=2 x y , then y^ (x) at x=0 is equal to
More Limit, Continuity and Differentiability questions · Browse all practice questions