5.6 liter of helium gas at STP is adiabatically compressed to 0.7 liter. Taking the…
Physics · NEET · NTA Exams — Thermodynamics
5.6 liter of helium gas at STP is adiabatically compressed to 0.7 liter. Taking the initial temperature to be T1, the work done in the process is
- \(\frac{9}{8} R T_{1}\)
- \(\frac{3}{2} R T_{1}\)
- \(\frac{15}{8} R T_{1}\)
- \(\frac{9}{2} R T_{1}\)
Answer
(A) 9 8 R T_ 1
Sign up free on Edukali to view the step-by-step worked solution and practice thousands of similar questions.
Related practice questions
- In an adiabatic process, the state of a gas in changed from P 1 , V 1 , T 1 to P 2 , V 2 , T 2 . Which of the…
- When an ideal gas is compressed adiabatically, its temperature rises the molecules on the average have more…
- A heat engine is involved with exchange of heat of 1915 J, -40 J, +125 J QJ, during one cycle achieving an…
- A litre of dry air at STP expands adiabatically to a volume of 3 litres. If = 1.40, the work done by air is …
- Internal energy change during a reversible isothermal expansion of an ideal gas is:
- The work done, when a gas at P 1 , V 1 changes to P 2 and V 2 adiabatically,
- Ten moles of an ideal gas at constant temperature 500 K is compressed from 50 L to 5 L. Work done in the…
- During an adiabatic process, the pressure of a gas is found to be proportional to the cube of its absolute…
More Thermodynamics questions · Browse all practice questions