Ten moles of an ideal gas at constant temperature 500 K is compressed from 50 L to 5 L…
Physics · NEET · NTA Exams — Thermodynamics
Ten moles of an ideal gas at constant temperature 500 K is compressed from 50 L to 5 L. Work done in the process is (Given, R = 8.31 J-mol-1-K-1):
- \(\text { — }\)1.2 \(x\) 104 J
- \(\text { — }\)2.4 \(x\) 104 J
- \(\text { — }\)4.8 \(x\) 104 J
- \(\text { — }\)9.6 \(x\) 104 J
Answer
(D) — 9.6 x 10 4 J
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