A bag P (mass M) hang by a long thread and a bullet (mass m) comes horizontally with…

Physics · JEE Advanced · NTA Exams — Laws of Motion

1. momentum is mv throughout
2. momentum is (M + m)v throughout
3. kinetic energy is \(\frac{1}{2} m v^{2}\) throughout
4. loss in kinetic energy in collision process is \(\frac{1}{2} m v^{2}\left(\frac{M}{M+m}\right)\)

Answer

(A) momentum is mv throughout, (D) loss in kinetic energy in collision process is 1 2 m v^ 2 ( M M+m )

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