Minimum thickness of a mica sheet having = 3 2 which should be placed in front of one of…
Physics · JEE Main · NTA Exams — Optics
Minimum thickness of a mica sheet having \(\mu=\frac{3}{2}\) which should be placed in front of one of the slits in YDSE is required to reduce the intensity at the centre of screen to half of maximum intensity is
- \(\frac{\lambda}{4}\)
- \(\frac{\lambda}{8}\)
- \(\frac{\lambda}{2}\)
- \(\frac{\lambda}{3}\)
Answer
(C) 2
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