A fish is a little away below the surface of a lake. If the critical angle is 49°, then…
Physics · JEE Main · NTA Exams — Optics
A fish is a little away below the surface of a lake. If the critical angle is 49°, then the fish could see things above the water surface within an angular ring of θ° where


- θ = 49°
- θ = 90°
- θ = 98°
- θ = \(2 \frac{1}{2} \circ\)
Answer
(C) θ = 98°
Sign up free on Edukali to view the step-by-step worked solution and practice thousands of similar questions.
Related practice questions
- Parallel rays of light are focussed by a thin convex lens. A thin concave lens of same focal length is then…
- A beam of monochromatic blue light of wavelength 4200 A in air travels in water of refractive index 4/3. Its…
- In YDSE, the source placed symmetrically with respect to the slit is now moved parallel to the plane of the…
- In Young’s double slit experiment, a mica sheet of thickness t and refractive index is introduced in the path…
- In the Young’s double slit experiment, the two equally bright slits are coherent, but of phase difference 3 …
- The refracting angle of prism is A and refractive index of material of prism is - . The angle of minimum…
- The diagram below shows, two sources A and B, vibrating in phase, in the same uniform medium and producing…
- A small plane mirror is placed at the centre of a spherical screen of radius R. A beam of light is falling on…