A particle of mass 'm' is projected with a velocity v = kV e (k < 1) from the surface of…
Physics · NEET · NTA Exams — Gravitation
A particle of mass 'm' is projected with a velocity v = kVe(k < 1) from the surface of the earth.
(Ve = escape velocity)
The maximum height above the surface reached by the particle is
- \(\frac{\mathrm{Rk}^{2}}{1-\mathrm{k}^{2}}\)
- \(R\left(\frac{k}{1-k}\right)^{2}\)
- \(R\left(\frac{k}{1+k}\right)^{2}\)
- \(\frac{R^{2} \mathbf{k}}{1+k}\)
Answer
(A) Rk ^ 2 1- k ^ 2
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