A particle of mass 'm' is projected with a velocity v = kV e (k < 1) from the surface of…

Physics · NEET · NTA ExamsGravitation

A particle of mass 'm' is projected with a velocity v = kVe(k < 1) from the surface of the earth.

(Ve = escape velocity)

The maximum height above the surface reached by the particle is

  1. \(\frac{\mathrm{Rk}^{2}}{1-\mathrm{k}^{2}}\)
  2. \(R\left(\frac{k}{1-k}\right)^{2}\)
  3. \(R\left(\frac{k}{1+k}\right)^{2}\)
  4. \(\frac{R^{2} \mathbf{k}}{1+k}\)

Answer

(A) Rk ^ 2 1- k ^ 2

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