A body weighs W newton at the surface of the Earth. Its weight at a height equal to half…
Physics · NEET · NTA Exams — Gravitation
A body weighs W newton at the surface of the Earth. Its weight at a height equal to half the radius of the Earth, will be
- \(\frac{W}{2}\)
- \(\frac{2 W}{3}\)
- \(\frac{4 W}{9}\)
- \(\frac{8 \mathrm{~W}}{27}\)
Answer
(C) 4 W 9
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