For the redox reaction Zn(s) + Cu 2+ (0.1 M) → Zn 2+ (1 M) + Cu (s) taking place in a…
Chemistry · JEE Main · NTA Exams — Redox Reactions and Electrochemistry
For the redox reaction
Zn(s) + Cu2+ (0.1 M) → Zn2+ (1 M) + Cu (s)
taking place in a cell, \(\mathrm{E}_{\mathrm{cell}}^{o}\) is 1.10V. \(\mathrm{E}_{\mathrm{cell}}^{o}\) for the cell will be \(\left(2.303 \frac{\mathrm{RT}}{\mathrm{~F}}=0.0591\right)\)
Zn(s) + Cu2+ (0.1 M) → Zn2+ (1 M) + Cu (s)
taking place in a cell, \(\mathrm{E}_{\mathrm{cell}}^{o}\) is 1.10V. \(\mathrm{E}_{\mathrm{cell}}^{o}\) for the cell will be \(\left(2.303 \frac{\mathrm{RT}}{\mathrm{~F}}=0.0591\right)\)
- 2.14 V
- 1.80 V
- 1.07 V
- 0.82 V
Answer
(C) 1.07 V
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