The equivalent weight of MnSO 4 is half its molecular weight when it is converted to
Chemistry · JEE Main · NTA Exams — Redox Reactions and Electrochemistry
The equivalent weight of MnSO4 is half its molecular weight when it is converted to
- Mn2O3
- MnO2
- \(\underset{\downarrow}{\mathrm{MnSO}_{4}} \underset{\rightarrow}{\mathrm{Mn}_{2} \mathrm{O}_{3}} \underset{\rightarrow+}{\mathrm{MnO}_{2}} \underset{\rightarrow}{\mathrm{MnO}_{4}^{-}} \underset{\rightarrow}{\mathrm{MnO}_{4}^{2-}} \underset{+6}{\mathrm{MnO}_{4}^{2-}}\)
- \(\left[2 \mathrm{e}^{-}+\underset{+2}{\mathrm{MnSO}_{4}} \rightarrow \underset{+4}{\mathrm{MnO}_{2}}\right] \mathrm{n}=2\)
Answer
(B) MnO 2
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