The sum of n terms of the following series 1 + (1 + x) + (1 + x + x 2 ) + . . . will be

Mathematics · JEE Advanced · NTA Exams — Progression and Series

1. \(\frac{1-x^{n}}{1-x}\)
2. \(\frac{x\left(1-x^{n}\right)}{1-x}\)
3. \(\frac{n(1-x)-x\left(1-x^{n}\right)}{(1-x)^{2}}\)
4. none

Answer

(C) n(1-x)-x (1-x^ n ) (1-x)^ 2

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