The sum of the n terms of the series 1 + (1 + 3) + (1 + 3 + 5) ....
Mathematics · JEE Advanced · NTA Exams — Progression and Series
The sum of the n terms of the series
1 + (1 + 3) + (1 + 3 + 5) ....
1 + (1 + 3) + (1 + 3 + 5) ....
- n2
- \(\left[\frac{\mathrm{n}(\mathrm{n}+1)}{2}\right]^{2}\)
- \(\left[\frac{\mathrm{n}(\mathrm{n}+1)(2 \mathrm{n}+1)}{6}\right]\)
- none of these
Answer
(C) [ n ( n +1)(2 n +1) 6 ]
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