When an alternating voltage E = E 0 sin t is applied to a circuit, a current I = I 0 sin…
Physics · Class 12 · CBSE — Alternating Current
When an alternating voltage E = E0 sin \(\omega\) t is applied to a circuit, a current I = I0 sin \(\left(\omega t+\frac{\pi}{2}\right)\) flows through it. The average power dissipated in the circuit is
- \(\mathrm{E}_{\mathrm{rms}} \cdot \mathrm{I}_{\mathrm{rms}}\)
- \(\mathrm{E}_0 \mathrm{I}_0\)
- \(\frac{E_0 I_0}{\sqrt{2}}\)
- Zero
Answer
(D) Zero
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