A resistor of 500 Ω and an inductance of 0.5 H are in series with an ac source which is…
Physics · Class 12 · CBSE — Alternating Current
A resistor of 500 Ω and an inductance of 0.5 H are in series with an ac source which is given by V =
sin(1000t). The power factor of the combination is


- 0.5
- 0.6
Answer
(A)
Sign up free on Edukali to view the step-by-step worked solution and practice thousands of similar questions.
Related practice questions
- A planar loop is rotated in a magnetic field about an axis perpendicular to the field. The polarity of…
- The voltage over a cycle varies as The average value of the voltage for one cycle is
- Figure shows the variation of inductive reactance X _ L of two ideal inductors of inductance L_ 1 and L_ 2 …
- In an ac circuit, V and I are given by V = 150sin(150 t ) volt and I = 150sin ampere. The power dissipated in…
- If V = 100sin(100 t ) V and I = 100sin (100 t+ 3 ) mA are the instantaneous values of voltage and current…
- Electrical energy is transmitted over large distances at high alternating voltage. Which of the following…
- A series LCR circuit with R = 22 Ω, L = 1.5 H and C = 40 μF is connected to a variable frequency 220 V ac…
- A resistor and an ideal inductor are connected in series to a 100 2 ~V , 50 Hz ac source. When a voltmeter is…
More Alternating Current questions · Browse all practice questions