A particle is executing a simple harmonic motion. Its maximum acceleration is α and…

Physics · JEE Main · NTA ExamsOscillations and Waves

A particle is executing a simple harmonic motion. Its maximum acceleration is α and maximum velocity is β. Then, its time period of vibration will be;-
  1. \(\frac{2 \pi \beta}{\pi}\)
  2. \(\frac{\beta^{2}}{a^{2}}\)
  3. \(\frac{\pi}{\beta}\)
  4. \(\frac{\beta^{2}}{x}\)

Answer

(A) 2

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