In a gravity free space, a man of mass M standing at a height h above the floor, throws a…
Physics · JEE Main · NTA Exams — Laws of Motion
In a gravity free space, a man of mass M standing at a height h above the floor, throws a ball of mass m straight down with a speed u. When the ball reaches the floor, the distance of the man above the floor will be :
- \(h\left(1+\frac{m}{M}\right)\)
- \(\left(1+\frac{\mathbf{M}}{\mathbf{m}}\right) \mathbf{h}\)
- h
- \(\frac{\mathbf{m}}{\mathbf{M}} \mathbf{h}\)
Answer
(A) h (1+ m M )
Sign up free on Edukali to view the step-by-step worked solution and practice thousands of similar questions.
Related practice questions
- In a situation the contact force by a rough horizontal surface on a body placed on it has constant magnitude…
- A force of 50 N is required to push a car on a level road with constant speed of 10 m/s. The mass of the car…
- A block is placed on the top of a smooth inclined plane of inclination kept on the floor of a lift. When the…
- Consider the following two statements : (A) Linear momentum of the system remains constant (B) Centre of mass…
- A shell is fired from cannon with a velocity v at an angle θ with the horizontal direction. At the highest…
- Given below are two statements. STATEMENT - 1: The coefficient of restitution for a perfectly inelastic…
- In the above problem, the acceleration of the lighter mass will be
- A car is running on a highway turning having a curved track of radius 145 m banked at an angle of 11.5^…
More Laws of Motion questions · Browse all practice questions