The equilibrium constant for the decomposition of water, [ H _ 2 O ( ~g ) H _ 2 ( ~g )+ 1…
Chemistry · JEE Advanced · NTA Exams — Equilibrium
The equilibrium constant for the decomposition of water,
\(\left[\mathrm{H}_{2} \mathrm{O}(\mathrm{~g}) \rightleftharpoons \mathrm{H}_{2}(\mathrm{~g})+\frac{1}{2} \mathrm{O}_{2}(\mathrm{~g})\right]\)
is given by :
\(\left[\mathrm{H}_{2} \mathrm{O}(\mathrm{~g}) \rightleftharpoons \mathrm{H}_{2}(\mathrm{~g})+\frac{1}{2} \mathrm{O}_{2}(\mathrm{~g})\right]\)
is given by :
- \(K=\frac{\alpha^{3} p^{1 / 2}}{(1-\alpha)(2-\alpha)^{1 / 2}}\)
- \(K=\frac{\alpha^{3 / 2} p^{1 / 2}}{(1-\alpha)(2+\alpha)^{1 / 2}}\)
- \(\mathrm{K}=\frac{\alpha^{3} \mathrm{p}^{1 / 2}}{\sqrt{2}}\)
- \(K=\frac{\alpha^{3} p^{3 / 2}}{(1-\alpha)(2+\alpha)^{1 / 2}}\)
Answer
(B) K= ^ 3 / 2 p^ 1 / 2 (1- )(2+ )^ 1 / 2
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