The period of oscillation of a simple pendulum of length L suspended from the roof of a…
Physics · JEE Advanced · NTA Exams — Oscillations and Waves
The period of oscillation of a simple pendulum of length L suspended from the roof of a vehicle which moves without friction down an inclined plane of inclination \(\boldsymbol{a}\), is given by
- \(2 \pi \sqrt{\frac{L}{g \cos \alpha}}\)
- \(2 \pi \sqrt{\frac{L}{g \sin \alpha}}\)
- \(2 \pi \sqrt{\frac{L}{g}}\)
- \(2 \pi \sqrt{\frac{L}{g \tan \alpha}}\)
Answer
(A) 2 L g
Sign up free on Edukali to view the step-by-step worked solution and practice thousands of similar questions.
Related practice questions
- Maximum velocity in SHM is V _ m . The average velocity during motion from one extreme point to the other…
- A simple pendulum has time period T = 2s is air. If whole arrangement is placed in non-viscous liquid whose…
- A particle moves according to the law x = a cos t 2 . The distance covered by it in the time interval between…
- The total length of a sonometer wire between fixed ends is 110 cm. Two bridges are placed to divide the…
- A particle executes simple harmonic motion between x = –A and x = +A . The time taken for it to go from 0 to…
- A student is performing the experiment of Resonance Column. The diameter of the column tube is 4 cm. The…
- Assertion: Both transverse and longitudinal mechanical waves can propagate in solids but only longitudinal…
- Three masses 700 g , 500 g , and 400 g are suspended at the end of as spring as shown and are in equilibrium…
More Oscillations and Waves questions · Browse all practice questions