For a monatomic gas kinetic energy = E. The relation with rms velocity is (2004)
Chemistry · JEE Advanced · NTA Exams — States of Matter (Gases and Liquids)
For a monatomic gas kinetic energy = E. The relation with rms velocity is (2004)
- \(u=\left(\frac{2 E}{m}\right)^{1 / 2}\)
- \(u=\left(\frac{3 E}{2 m}\right)^{1 / 2}\)
- \(\mathrm{u}=\left(\frac{\mathrm{E}}{2 \mathrm{~m}}\right)^{1 / 2}\)
- \(\mathrm{u}=\left(\frac{\mathrm{E}}{3 \mathrm{~m}}\right)^{1 / 2}\)
Answer
(A) u= ( 2 E m )^ 1 / 2
Sign up free on Edukali to view the step-by-step worked solution and practice thousands of similar questions.
Related practice questions
- Assertion (A): When hydrogen gas expands adiabatically from high pressure to low pressure at room temperature…
- At what temperature will the average speed of CH 4 molecules have the same value as O 2 has at 300 K ?
- At constant volume, for a fixed number of moles of a gas the pressure of the gas increases with rise of…
- How many O 2 molecules are present in 2.0 L of oxygen gas at 27 o C temperature and 3.0 atm pressure ?
- A mixture of CO and CO 2 is found to have a density of 1.5 g/L at 30 0 C and 730 torr. The composition of…
- NH 3 can be liquefied at ordinary temperature without the application of pressure. But O 2 cannot, because
- Among the plots, which of them represent Charle’s law, at constant pressure ?
- At N.T.P. the volume of a gas is found to be 273 mL. what will be the volume of this gas at 600 mm Hg and…
More States of Matter (Gases and Liquids) questions · Browse all practice questions