The solution of e^ d y d x =(x+1) where y(0)=3 , is

Mathematics · JEE Main · NTA Exams — Differential Equations

1. \(\mathbf{y}=\mathbf{x} \log \mathbf{x}-\mathbf{x}+\mathbf{z}\)
2. \(y=(\mathbf{x}+1) \log (\mathbf{x}+1)-\mathbf{x}+\mathbf{3}\)
3. \(y=(\mathbf{x}+1) \log (\mathbf{x}+1)+\mathbf{x}+\mathbf{3}\)
4. \(\mathbf{y}=\mathbf{x} \log \mathbf{x}+\mathbf{x}+\mathbf{3}\)

Answer

(B) y=( x +1) ( x +1)- x + 3

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