A simple pendulum performs simple harmonic motion about x = 0 with an amplitude a and…
Physics · JEE Main · NTA Exams — Oscillations and Waves
A simple pendulum performs simple harmonic motion about x = 0 with an amplitude a and time period T. The speed of the pendulum at \(x=\frac{a}{2}\) is \(\frac{\pi a \sqrt{n}}{T}\), find the value of n
- \(\frac{\pi \mathrm{a} \sqrt{3}}{2 \mathrm{~T}}\)
- \(\frac{\pi \mathrm{a}}{\mathrm{~T}}\)
- \(\frac{3 \pi^{2} \mathrm{a}}{\mathrm{~T}}\)
- \(\frac{\pi a \sqrt{3}}{T}\)
Answer
(D) a 3 T
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