A transverse wave is described by the equation y=y_ 6 2 (f t- x ) The maximum particle…
Physics · JEE Main · NTA Exams — Oscillations and Waves
A transverse wave is described by the equation \(y=y_{6} \sin 2 \pi\left(f t-\frac{x}{\lambda}\right)\)
The maximum particle velocity is equal to four times the wave velocity if
The maximum particle velocity is equal to four times the wave velocity if
- \(\lambda=\frac{\pi y_{0}}{4}\)
- \(\lambda=\frac{\pi y_{0}}{2}\)
- \(\lambda=\pi y_{0}\)
- \(\lambda=2 \pi y_{0}\)
Answer
(B) = y_ 0 2
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