The solution of primitive equation ( x 2 + y 2 ) dy = xy dx , is y = y ( x ). If y (1) =…
Mathematics · JEE Advanced · NTA Exams — Differential Equations
The solution of primitive equation
(x2 + y2) dy = xy dx, is y = y (x). If y (1) = 1
and y (x0) = e, then x0 is
(x2 + y2) dy = xy dx, is y = y (x). If y (1) = 1
and y (x0) = e, then x0 is
Answer
(A)
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