Two identical photo-cathodes receive light of frequencies f 1 and f 2 . If the velocities…
Physics · JEE Advanced · NTA Exams — Atoms and Nuclei
Two identical photo-cathodes receive light of frequencies f1 and f2. If the velocities of the photo electrons (of mass m) coming out are respectively ν1 and ν2, then
- \(v_{1}-v_{2}=\left[\frac{2 h}{m}\left(f_{1}-f_{2}\right)\right]^{1 / 2}\)
- \(v_{1}^{2}-v_{2}^{2}=\frac{2 h}{m}\left(f_{1}-f_{2}\right)\)
- \(v_{1}+v_{2}=\left[\frac{2 h}{m}\left(f_{1}+f_{2}\right)\right]^{1 / 2}\)
- \(v_{1}^{2}+v_{2}^{2}=\frac{2 h}{m}\left(f_{1}+f_{2}\right)\)
Answer
(B) v_ 1 ^ 2 -v_ 2 ^ 2 = 2 h m (f_ 1 -f_ 2 )
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