Two blocks of the same metal having same mass and at temperature T 1 and T 2 …
Chemistry · NEET · NTA Exams — Chemical Thermodynamics
Two blocks of the same metal having same mass and at temperature T1 and T2, respectively are brought in contact with each other and allowed to attain thermal equilibrium at constant pressure. The change in entropy, ΔS, for this process is:
- \(\mathbf{2 C} \mathbf{C}_{\mathbf{p}} \ln \left(\frac{T_{1}+T_{2}}{4 T_{1} T_{2}}\right)\)
- \(\mathbf{2 C} \mathbf{C}_{p} \ln \left[\frac{\left(T_{1}+T_{2}\right)^{\frac{1}{2}}}{T_{1} T_{2}}\right]\)
- \(C_{p} \ln \left[\frac{\left(T_{1}+T_{2}\right)^{2}}{4 T_{1} T_{2}}\right]\)
- \(\mathbf{2 C _ { p }} \boldsymbol{\operatorname { l n }} \boldsymbol{\operatorname { l n }}\left[\frac{T_{1}+T_{2}}{\mathbf{2 T _ { 1 } T _ { 2 }}}\right]\)
Answer
(C) C_ p [ (T_ 1 +T_ 2 )^ 2 4 T_ 1 T_ 2 ]
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