Oxidising power of chlorine in aqueous solution can be determined by the parameters…

Chemistry · NEET · NTA ExamsChemical Thermodynamics

Oxidising power of chlorine in aqueous solution can be determined by the parameters indicated below: 

\(\frac{1}{2} \mathrm{Cl}_{2}(\mathrm{~g}) \xrightarrow{\frac{1}{2} \mathrm{~A}_{d s s} \mathrm{H}^{\infty}} \mathrm{Cl}(\mathrm{~g}) \xrightarrow{\mathrm{A}_{k A} \mathrm{H}^{\infty}}\)

\(\mathrm{Cl}^{-}(\mathrm{g}) \xrightarrow{\Delta_{\mathrm{hmd}} \mathrm{H}^{\mathrm{a}}} \mathrm{Cl}^{-}(\mathrm{aq})\)

The energy involved in the conversion of \(\frac{1}{2} \mathrm{Cl}_{2}(\mathrm{~g})\) to Cl- (aq)

Using the data,

\(\Delta_{\mathrm{dims}} \mathrm{H}_{\mathrm{Cl}_{2}}^{\prime \prime}=240 \mathrm{~kJ} \mathrm{~mol}^{-1} .\)

\(\Delta_{\mathrm{EA}} \mathrm{H}_{\mathrm{Cl}}=-349 \mathrm{~kJ} \mathrm{~mol}^{-1} .\)

\(\Delta_{\mathrm{hyd}} \mathrm{H}_{\mathrm{cl}}^{e}=-381 \mathrm{~kJ} \mathrm{~mol}^{-1}\) will be:

  1. + 152 kJ mol-1
  2. - 610 kJ mol-1
  3. - 850 kJ mol-1
  4. + 120 kJ mol-1

Answer

(C) - 850 kJ mol -1

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