Oxidising power of chlorine in aqueous solution can be determined by the parameters…
Chemistry · NEET · NTA Exams — Chemical Thermodynamics
\(\frac{1}{2} \mathrm{Cl}_{2}(\mathrm{~g}) \xrightarrow{\frac{1}{2} \mathrm{~A}_{d s s} \mathrm{H}^{\infty}} \mathrm{Cl}(\mathrm{~g}) \xrightarrow{\mathrm{A}_{k A} \mathrm{H}^{\infty}}\)
\(\mathrm{Cl}^{-}(\mathrm{g}) \xrightarrow{\Delta_{\mathrm{hmd}} \mathrm{H}^{\mathrm{a}}} \mathrm{Cl}^{-}(\mathrm{aq})\)
The energy involved in the conversion of \(\frac{1}{2} \mathrm{Cl}_{2}(\mathrm{~g})\) to Cl- (aq)
Using the data,
\(\Delta_{\mathrm{dims}} \mathrm{H}_{\mathrm{Cl}_{2}}^{\prime \prime}=240 \mathrm{~kJ} \mathrm{~mol}^{-1} .\)
\(\Delta_{\mathrm{EA}} \mathrm{H}_{\mathrm{Cl}}=-349 \mathrm{~kJ} \mathrm{~mol}^{-1} .\)
\(\Delta_{\mathrm{hyd}} \mathrm{H}_{\mathrm{cl}}^{e}=-381 \mathrm{~kJ} \mathrm{~mol}^{-1}\) will be:
- + 152 kJ mol-1
- - 610 kJ mol-1
- - 850 kJ mol-1
- + 120 kJ mol-1
Answer
(C) - 850 kJ mol -1
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