Consider the reaction 4HNO 3 (l) + 3KCl(s) → Cl 2 (g) + NOCl(g) + 2H 2 O(g) + 3KNO 3 (s)…
Chemistry · JEE Main · NTA Exams — Some Basic Concepts in Chemistry
Consider the reaction
4HNO3(l) + 3KCl(s) → Cl2(g) + NOCl(g) + 2H2O(g) + 3KNO3(s)
The amount of HNO3 required to produce 110.0 g of KNO3 is :
(Given: Atomic masses of H, O, N and K are 1, 16, 14 and 39, respectively.) (JEE Main 2022)
4HNO3(l) + 3KCl(s) → Cl2(g) + NOCl(g) + 2H2O(g) + 3KNO3(s)
The amount of HNO3 required to produce 110.0 g of KNO3 is :
(Given: Atomic masses of H, O, N and K are 1, 16, 14 and 39, respectively.) (JEE Main 2022)
- 32.2 g
- 69.4 g
- 91.5 g
- 162.5 g
Answer
(C) 91.5 g
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