If the roots of the equation, x 3 + Px 2 + Qx – 19 = 0 are each one more than the roots…
Mathematics · JEE Advanced · NTA Exams — Complex Numbers and Quadratic Equations
If the roots of the equation, x3 + Px2 + Qx – 19 = 0 are each one more than the roots of the equation,
x3–Ax2+Bx–C=0 where A, B, C, P and Q are constants then the value of A + B + C =
x3–Ax2+Bx–C=0 where A, B, C, P and Q are constants then the value of A + B + C =
- \(18\)
- \(20\)
- \(17\)
- \(19\)
Answer
(A) 18
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