If the roots of the equation, x 3 + Px 2 + Qx – 19 = 0 are each one more than the roots…

Mathematics · JEE Advanced · NTA ExamsComplex Numbers and Quadratic Equations

If the roots of the equation, x3 + Px2 + Qx – 19 = 0 are each one more than the roots of the equation,
x3–Ax2+Bx–C=0 where A, B, C, P and Q are constants then the value of A + B + C =
  1. \(18\)
  2. \(20\)
  3. \(17\)
  4. \(19\)

Answer

(A) 18

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